Question

3. An aqueous solution boils at 100.50°C. The freezing point of the solution would be (Ko for water =
0.51°C/m). (K for water = 1.86°C/m) [No association or dissociation)
(A) 0°C
(B)- 1.86°C
(C) - 1.82°C (D) + 1.82°C

Answer 1

Answer:

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Explanation:

An aqueous solution boils at 100.50∘C. The freezing point of the solution would be (Kb for water =0.51∘C/m),(Kf for water =1.86∘C/m) [no association or dissociation]

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Answer 2

Explanation:

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