Question

3. An automobile starting at rest (m/s) increases to a velocity of 31 m/sec in 2
seconds. What was the acceleration of this vehicle?​

Answer 1

Answer:

Given :-

Final velocity = 31 m/s

Initial velocity = 0 m/s

Time = 2 sec

To Find :-

Acceleration

Solution :-

We know that

${ \boxed{ \pink{ \underline{ \mathfrak{a = \dfrac{v - u}{t} }}}}}$

Where,

a = acceleration

v = final velocity

u = initial velocity

t = time

$\sf \: a \: = \dfrac{31 - 0}{2}$

$\sf \: a \: = \dfrac{31}{2}$

$\bf \red{a = 15.5 \: {m/s}^{2} }$

Therefore,

Acceleration is 15 m/s²

Answer 2

Answer:

Given :-

a man start walking and cover 3 meters in north direction then he turn right and cover 4 metre. from this point again he walks north direction and covered 3 meters distance then he take another right and cover 4 metre distance

To Find :-

The total distance travel and total displacement

Solution :-

Finding the total distance

Distance = 3 + 3 + 4 + 4

Distance = 6 + 8

Distance = 14 m

Finding total displacement

We may observe that the North and East make a right angle triangle.

By using Pythagorean theorem

H² = P² + B²

$\sf \: {H}^{2} = {6}^{2} + {8}^{2}$

$\sf \: {H}^{2} = 36 + 64$

$\sf \: {H}^{2} = 100$

$\sf \: {H} = \sqrt{100}$

$\sf \: H = 10 \: m$