Question

3.An electric dipole when held at 30° with respect to a uniform electric field of 10^(4)N/C experience a torque of 9x10^(-26)NM calculate dipole moment of the dipole​

Answer 1

Answer:

hello the answer is-

Electric dipole moment, p = 4 × 10−9 C m (Given)

Angle made by p with a uniform electric field, θ = 30° (Given)

Electric field, E = 5 × 104 N C−1 (Given)

Torque acting on the dipole is given by the relation,

τ = pE sinθ

= 4 × 10-9 × 5 × 104 × sin 30

= 20 × 10-5 × 1 half

Answer 2

Answer:

$\bigstar{\bold{Dipole\:moment=4.5\times 10^{-30} C\:m }}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Electric field (E) = 10⁴ N/C
• Torque (τ) = 9 × 10⁻²⁶ N m
• Angle (θ) = 30°

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• To find dipole moment (p)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ We need to find the dipole moment of the dipole

→ We know that torque acting ona body is given by the equation,

   τ = p E sinθ

→ Substituting the given datas we get the value of p

  9 × 10⁻²⁶ = p × 10⁴ × sin 30

  9 × 10⁻²⁶ = p × 10⁴ × 1/2

  p/2 = 9 × 10⁻²⁶/10⁴

  p/2 = 9 × 10⁻³⁰

      p = 4.5 × 10⁻³⁰ C m

→ Hence dipole moment is 4.5 × 10⁻³⁰ C m

$\boxed{\bold{Dipole\:moment=4.5\times 10^{-30} C\:m }}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ An electric dipole is a pair of equal and opposite charges separated by some distance.

p = 2 × a × q

where q is the charge of a dipole and 2a is the distance between them.