Question

3. An elevator descends into a mine shaft at the rate of 6 m/min. If it descends from 10 m above the ground level, how long it will take to reach -350 m(below the ground)?

Answer 1

Answer:

Step-by-step explanation:

Speed of elevator = 6 m/min

Converting speed into m/s = 6/60

                                             = 0.1 m/s

Distance to be covered by the elevator = 350 + 10

                                                                  = 360 m

We know  that Speed = Distance/Time

Let the time be t

0.1 = 360 / t

t = Distance/Speed

t = 360/ 0.1

t = 3600 sec

t = 1 hour

So, the  time taken by the elevator to reach the desired position = 1 hour

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