3. An elevator descends into a mine shaft at the rate of 8m/min. If the descends
start from 20m above the ground level, how long will it take to reach-400m?
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Answer:
here as the distance covered below the ground is given (-)400 m , we will omit that (-) sign as it's just given to denote downwards direction and distance traveled can't be negative.
starting distance above the ground = 20m
distance to be covered below it = 400m
total distance to be covered = 420m
speed = 8m/min
therefore, time taken = distance/speed
= 420/8
Answer = 52.5min
hope it helped
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