Question

3. An LCR circuit of R = 100 2 is connected to an AC source 100 V, 50 Hz. The magnitude of phase difference between current and voltage is 30°. The power dissipated in the LCR circuit is :
(a) 50 W
(b) 86.6 W
(C) 100 W
(d) 200 W
​

Answer 1

ANSWER:-

R=100Ω,V=100V,θ=30

Phase angle, tanθ= RX L

= RX C

⇒tan30 = RX L

= RX C

∴X L

=X C

= 3 R

i.e. Z= R 2 +( 3R− 3 R) 2 =R

So, average power,P= RV 2

= =100W

Answer 2

Answer:

hi mate

here is your answer

option (c)

100 w

hope it helped you ✌

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