3
An object accelerates from rest to a velocity 30 m/s
in 10 s, then find distance covered by the object
during next 10 s
(1 450 m (2) 300 m
(3) 150 m (4) 600 m
The velocity time
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here is ur answer mate
Explanation:
hope it helps you out
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Answer:
(3) 150m
Explanation:
a = v-u/t
= 30-0/10
a = 3m/s
s = ut +1/2 at²
= 0 + 1/2 ×3 ×10×10
= 15×10
= 150 m
OR
v² - u² = 2as
30²-0 = 2×30×s
900/ 60 = s
s= 15
after 10 s = 150 m
❤HOPE THIS HELPS U ❤
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