Question

3. An object of mass 100 kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6 sec. Calculate initial and initial and final momentum of object. Also find magnitude of the force exerted on the object
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Answer 1

Answer:

Explanation:

Given,

Mass of the object, m = 100 kg

Initial velocity of the object, u = 5 m/s

Final velocity of the object, v = 8 m/s

Time taken by the object, t = 6 seconds

To Find,

Initial momentum

Final momentum

Force exerted

Formula to be used,

Initial momentum = mu

Final momentum = mv

Force exerted = (mv - mu)/t

Solution,

Putting all the values, we get

Initial momentum = mu

⇒ Initial momentum = 100 × 5

⇒ Initial momentum = 500 kg m/s

Hence, the initial momentum of object is 500 kg m/s.

Now, final momentum of object,

Final momentum = mv

⇒ Final momentum = 100 × 8

⇒ Final momentum = 800 kg m/s

Hence, the final momentum of object is 800 kg m/s.

Now, force exerted on the object,

Force exerted = (mv - mu)/t

⇒ Force exerted = (800 - 500)/6

⇒ Force exerted = 300/6

⇒ Force exerted = 50 N

Hence, the force exerted on the object is 50N.

Answer 2

Answer:

Given :-

• Mass of object = 100 kg
• Initial velocity = 5 m/s
• Final velocity = 8 m/s
• Time taken = 6 sec

To Find :-

• Initial mounmentum
• Final mounmentum
• Magnitude

Solution :-

As we know that

$\sf \red{ initial \: mounmentum = mu}$

$\sf \pink{initial \: mounmentum \: = 100 \times 5}$

$\sf \green {initial \:mounmentum = 500 kg m/s}$

$\sf \red{final \:mounmentum = mv}$

$\sf \green{final \: velocity = 100 \times 8 = 800 \: kg \: mps}$

$\sf \red {force \: exerted = \frac{mv - mu}{t} }$

$\sf \pink {force \: exerted = \frac{800 - 500}{6} }$

$\sf \green {force \: exerted \: = \dfrac{300}{6} }$

$\sf \pink{force \: exerted = 50 \: n}$