3. An object of size 3 cm is placed at a distance of 15 cm from a convex lens of focal length 10 cm. Calculate the distance and size of the image so formed. What will be the nature of image?
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pata nhi..................i think it should be 20
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height of object= 3cm
object distance= -15cm
focal length= 10cm
v=? h of image=?
1/f=1/v-1/u
1/v=1/f+1/u
1/v= 1/10+1/-15
1/v= -5/-150
v= -150/-5
v= 30cm
h of image= m*h of object
= v/u*h
= 30/-15*3
= -2*3
height of image = -6cm (-ve value because real and inverted)
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