Question

3. An observer standing between two cliffs fires a gun. He hears the first echo after 1 second and thenext after 3 seconds. Find(a) his distance from the nearer cliff.(b) his distance between the two cliffs.(Velocity of sound = 330 ms)

Answer 1

Answer:

Explanation:

Let Distance between both cliffs= d

D1 = Distance between observer and cliff no. 1

D2= Distance between cliff 2 and observer

Therefore D= D1 + D2

Using s= v*t  (s= displacement, v=velocity, t= time)

2D1=330*1 (For the echo to be heard, the sound needs to get to the cliff D1

and back again, hence  2D1

D1= 330/2 = 165m (This is the distance between observer and nearer cliff)

Doing the same thing for D2

2D2= 330*3

D2= 990/2  = 495m

D= D1+D2

D= 165+495

  =660m