3.
An oil drop of N excess electrons in held
stationary under a constant electric field E in
Millikan's oil drop experiment. The density of
the oil is p. Estimate the radius of the drop.
Answers
Answered by
1
Explanation:
Here n=10,E=3.65×10
4
NC
−1
,ρ
oil
=1.26gcm
−3
=1.26×10
3
kgm
−3
As the droplet is stationary, wheight of droplet = force due to electric field
or
3
4
πr
3
ρg=neE∴r
3
=
4πρg
3neE
∴r
3
=
4×3.14×1.26×10
3
×9.8
3×10×1.6×10
−19
×3.65×10
4
=1.13×10
−18
or r=(1.13×10
−18
)
1/3
=1.04×10
−6
m
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