3. An organic compound was found to contain the following constituents : C = 33%; H = 4.7%; N= 13.2%, Cl = 33-4%. Determine the empirical formula of the compound.
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Answered by
2
Answer:
An organic compund contains C = 40%, H = 13.33% and N = 46.67% . Its emperical formula
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""" ❤️ Answer ❤️ """
Given: Carbon:
16.27=
12
16.27
=
1.355
Hydrogen:
0.67=
1
0.67
=
0.67
Chlorine:
72.2=
3 5 . 5
7 2 . 2
=
2.03
Oxygen:
10.86=
16
10.86
=
0.67
Mole ratio
C:
H:
Cl:
O=
2:
1:
3:
1
Emperical formula=
3
C
2
E.F. weight=
24+
1+
106.5+
16=
147.5
Given, vapour density= 73.75
Molecular weight=
2×
V.D
=
2×
73.75
=
147.5
.
∴ Molecular Formula
3
C
2
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