Question

3 and -2 are the roots of the following quadratic equations

Answer 1

Answer:

x² -x -6 = 0

explanation ------=>

3 and -2 are the roots

so, their sum = 3 -2 = 1

and their product = 3 * -2 = -6

so,

required quadratic equation is

x² - ( sum)x + product = 0

=> x² - 1x + ( -6) = 0

or

x² -x - 6 = 0

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Answer 2

Answer:

$3 \: and \: - 2 \: are \: roots$

$so \: their \: sum = 3 - 2 = 1$

$and \: their \: product = 3 \times - 2 = - 6$

$so \: required \: quadratic \: equation \: is$

${x}^{2} - (sum)x + product = 0$

$⟹ {x}^{2} - 1x + ( - 6) = 0$

$⟹ {x}^{2} - x - 6 = 0$