Question

√3 and -√3 are zeroes of d (x)=x4-3x3-x2+9x-6 find all its zeroes​

Answer 1

Step-by-step explanation:

x=√3 , x= -√3 are the zeroes

x-√3=0 , x+√3=0

(x-√3)(x+√3)

x²-3

Then divide the x4-3x³-x²+9x-6 by x²-3

x²-3) x4-3x³-x²+9x-6 ( x²-3x+2

x4 -3x²

--------------------

-3x³+2x²+9x-6

-3x² +9x

---------------------

2x² -6

2x² -6

------------------

0

----------------

then factorise x²-3x+2

x²-3x+2 ( 1*2=2) , ( 1+2=3)

x²- ( 2+1)x +2

x²- 2x-1x +2

x (x-2) -1 (x-2)

(x-1) (x-2)

x-1=0, x-2=0

x=1 , x= 2

2 , 1 , √3, -√3 are the zeroes