Question

3 and -4 are roots of the quadratic equation find the quadratic equation​

Answer 1

Answer:

x²+x-12=0

Step-by-step explanation:

We know that

if a and b are the roots of quadratic equation

then equations can be written as

x²-(a+b)x+ab=0

According to the problem,

roots of this equation are 3 and -4.

hence,

required quadratic equation can be written as

x²-[3+(-4)]x+3x(-4)=0

x²-(-1)x+(-12)=0

x²+x-12=0

Answer 2

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Step-by-step explanation:

Since sum of roots is -b/a and product of roots is c/a

Sum of roots= 3+(-4)=-b/a

Product of roots=3×-4=c/a

Thus -b/a=-1 & c/a=-12

Thus quadratic equation is

X^2+x-12