Question

3. Angular momentum of the particle p moving parallel
to X-axis about origin O is (in kg-m2s-1)





(1) 50
(3) 80
(2) 60
(4) 100​

Answer 1

Answer:

Velocity=vi^

position vector=ai^+bj^

Angular momentum=m(ai^+bj^)x vi^

doing the cross product.

=mvb k^ is the angular momentum of the particle.

hope it helps