Question

3. Are the lines 3x - 5y = 19, 3y - 7x + 1 = 0 coincident?​

Answer 1

Step-by-step explanation:

Given :-

the lines 3x - 5y = 19, 3y - 7x + 1 = 0

To find:-

Are the lines 3x - 5y = 19, 3y - 7x + 1 = 0 coincident?

Solution:-

Given lines are:

3x-5y=19

=>3x-5y-19=0

a1=3;b1=-5;c1=-19

3y-7x+1=0

=>-7x+3y+1=0

a2=-7;b2=3;c2=1

now, a1/a2==3/-7=-3/7

b1/b2=-5/3

c1/c2=-19/1=-19

therefore,a1/a2≠b1/b2≠c1/c2

Given lines are not coincident lines.

Answer:-

Given lines are not coincident lines.

Used concept:-

If a1/a2≠b1/b2≠c1/c2 then the given lines are intersecting lines.

If a1/a2=b1/b2=C1/c2 then the lines are dependent or coincident lines with infinite number of many solutions

Answer 2

Answer:

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