3) Area of the given quadrilateral ABCD is 21 m2IF DE = 3 m and BF = 4 m then AC is
a) 8 m
b) 5 m
c) 6 m
d) 7 m
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Answer:
In ΔADE,
∠EAD+∠BAF=90o and
∠EAD+∠BAF=90o⇒∠EDA=∠BAF
⇒AFDE=BFAE
⇒BFAF=AEDE=35....(1)
similarly ΔCFB:ΔDEC
⇒BFCE=CFDE
⇒BFCF=CEDE=75...(2)
adding (1) and (2)
BFAF+CF=2150
⇒BFAC=2150
⇒BF10=21
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