Question

3 As the speed of a body becomes three times, its kinetic energy increases by ________
3 times
9 times
1 by 3times
1 by 9 times​

Answer 1

Answer:

Assuming you know the formula for calculating the kinetic energy of a body which is given by K.E= 1/2*m*v^2.(where m is the mass of the body,v is the velocity of the body )

Now according to the problem the velocity is increased 3 times.

So if we assume that the initial velocity of the body to be v m/s then the final velocity is 3v m/s.(as it is three times of the initial speed)

Now the new K.E is calculated by putting 3v as velocity in the equation to get the answer.

Thus Final K.E=1/2*m*(3v)^2=9*initial K.E.

So the final kinetic energy becomes 9 times of its initial kinetic energy.

Explanation:

Answer 2

Answer:

9 times.

Explanation:

K.E=1/2mv^2

=1/2m(3v)^2

=1/2m9v^2

=9(1/2mv^2)