Question

3. At normal temperature and pressure (NTP)
density of air is 1.293 kg m-3 and specific heat
at constant volume is 180 cal kg-1 K-1. Find the
value of specific heat at constant pressure.
(1) 274 cal kg-1 k-1 (2) 290 cal kg-1 K-1
(3) 248 cal kg-1 k-1 (4) 227 cal kg-1 K-1​

Answer 1

Answer:

Specific heat capacity at constant pressure is given as

$C_p = 248 \frac{cal}{kg K}$

Explanation:

As we know that by ideal gas equation we have

$PM = \rho RT$

so we have

$(10^5)M = 1.293 (8.31)(300)$

$M = 0.0322 kg$

now we can convert the specific heat capacity in terms of per mol

$C_v = 180 \frac{cal}{kg K}$

$C_v = 180 \times 0.0322\frac{cal}{mol K}$

$C_v = 5.796 \frac{cal}{mol K}$

now we have

$C_p = C_v + R$

$C_p = 5.796 + 2 = 7.796 \frac{Cal}{mol K}$

so we have

$C_p = 7.796 \frac{cal}{0.0322 kg K}$

$C_p = 248 \frac{cal}{kg K}$

#Learn

Topic : Specific heat capacity

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Answer 2

Answer:

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Explanation:

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