3 bags and 3 chairs together cost rs 2250 and 4 bags and 3 chairs cost rs 1950. find the cost of 2bags and 1 chairs
subodh23:
The question is completely wrong as how can the cost of 3bags and 3chairs be more than the cost of 4bags and 3chairs.
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solution:
Let the cost of one bag is rs x and cost of one chair is rs y
ATQ- 3x+ 3y= 2250.... (1)
x+ y= 750.....(3)
And, 4x+3y= 1950....(2)
subtracting 1 from 2. we get..
=> x = -300
putting the value of x in 3.
=> -300+y= 750
=> y= 1050..
Cost of one chair is 1050 and 2 bags is 2* 300= 600 ( ruppes can't be negative).
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☺
Let the cost of one bag is rs x and cost of one chair is rs y
ATQ- 3x+ 3y= 2250.... (1)
x+ y= 750.....(3)
And, 4x+3y= 1950....(2)
subtracting 1 from 2. we get..
=> x = -300
putting the value of x in 3.
=> -300+y= 750
=> y= 1050..
Cost of one chair is 1050 and 2 bags is 2* 300= 600 ( ruppes can't be negative).
_______________________________
☺
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