3 bags contain 3 red, 4 black balls, 4 red, 5 black balls; 5 red, 2 black balls. If one bag is selected at
random and a ball is drawn from it then the probability that it is red is
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Let P(R) denote the event of selecting a red ball.
From Baye's theorem,
P(R)=1/3(3/7)+1/3(4/9)+1/3(5/7)
The required probability is 1/7+4/27+5/21
8/21+4/27
0.529100529.
Hope it helps u........
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