Question

3. Balance the following equations:
(a) CH + O CO + H₂O
(b) Na, O + HO- NaOH
(c) Ca(OH), + HCI- CaCl + H,O
(d) Na + HO - NaOH + H,
(e) Na + Cl- NaCl
4. Complete the following equations.
(a) Iron + Oxygen + Water-
(b) Vinegar + Baking soda-
(c) Carbon dioxide + Lime water-
(d) Copper sulphate + Iron -




plz answer correct answer will be marked as brainlist​

Answer 1

Answer:

Answer to question 4:-

(a)Iron +Oxygen +Water

Fe + O_2 + H_2O \rightarrow Fe_2O_3

(Iron) + (Oxygen) + (Water) \rightarrow (Ferric Oxide or rust)

Explanation:

This above equation is the rusting process. When the iron comes in contact with oxygen along with water, it ends up forming ferric oxide, otherwise known as the rust.  Ferric oxide is in reddish brown color.

Some other oxides of iron are follows:

Iron(II) oxide (FeO) → Green-blue

Iron (II, III) oxide (magnetite) → Brown-red

Iron (III) oxide hematite → Rust

(b)Vinegar + Baking soda

Acetic acid present in vinegar will readily react with baking soda (sodium bicarbonate) to form sodium acetate with the effervescence of carbon dioxide. The equation for the reaction is: CH3COOH + NaHCO3 = CH3COONa + CO2 + H2O.

(c) Carbon dioxide + Lime water

CO2(g) + Ca(OH)2(aq) -----> CaCO3(s) + H2O(l)

The white milky suspension/precipitate is caused by the formation of calcium carbonate and explains the limewater test for carbon dioxide.

Bubbling carbon dioxide through the solution for an extended period of time makes the solution become clear and colourless as the carbon dioxide forms acidic carbonic acid when it dissolves in the water, the carbonic acid (H2CO3) reacts further with the calcium carbonate:

CO2 + H2O ------> H2CO3

H2CO3 +CaCO3 --------> Ca(HCO3)2

Ca(HCO3)2 = calcium hydrogen carbonate which is soluble in water.

This chemistry is important in understanding how hard water is formed and then lime scale is formed in kettles and hot water boilers.

(d) Copper sulfate + Water

CuSO4 (s) + HOH (l) --> Cu^+2 (aq) + SO4^-2 (aq) + HOH (l)