Math, asked by nikki5348, 5 months ago

3 bells ring at an interval of 4,7 and 14 minutes. All
three bell hang at 6 am, when the three balls will
the ring together next?​

Answers

Answered by joelpaulabraham
2

Answer:

They will ring together next at 6.28 am.

Step-by-step explanation:

We can solve it in two ways.

Method 1 (Actual method)

We have,

3 bells that ring at an interval of 4 mins., 7mins., and 14 mins.

So,

They will ring together at their 'common multiple' time or simply, at a time where all these 3 intervals come together, which just means when they ring together.

So,

LCM (4, 7, 14) = 28

Hence,

After every 28 mins. the bell ring together.

Now,

All the bells rang at 6 a.m, then they will ring together exactly after 28 mins.

So,

They will ring together next at 6.28 am.

Method 2 (Trial & Error)

Let's see when all these bells ring,

1st bell timings, 2nd bell timings, 3rd bell timings,

6.00 am 6.00 am 6.00 am

6.04 am 6.07 am 6.14 am

6.08 am 6.14 am 6.28 am

6.12 am 6.21 am 6.42 am

6.16 am 6.28 am .

6.20 am 6.35 am .

6.24 am . .

6.28 am . .

6.32 am . .

. . .

. . .

. . .

and so on...... and so on...... and so on.......

Here,

If you look closely all the clocks ring at 6.28 am after 6 am

Hence,

They will ring together next at 6.28 am.

Hope it helped and believing you understood it........All the best

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