Physics, asked by viveksaila21, 1 month ago

3. Block B is placed on a smooth surface Block A. is placed on a rough surface of Block B with coefficient of friction 0.60. The mass of A and B are 2kg and 4kg respectively. The frictional force between A and B (in N) is​

Answers

Answered by daiwikND
1

Answer:

8

Explanation:

Assume both blocks are accelerating towards left with acceleration a

a=f−22=20−f4 or f=8N

fmax=μmg=(0.6)(2)(10)=12N

So frictional force =8N

Answered by amikkr
1

Given: Mass of block A = 2kg

           Mass of block B = 4kg

           Coefficient of friction between block A and block B = 0.60    

To find: Frictional force between A and B

Solution:

Since block A is kept on the surface of block B, therefore the mass of the system = 2+4 = 6 kg

The total force of the system = 18N

Therefore, acceleration will be 3 m/s².

Now we will check frictional force

Fr - 2 = mass×acceleration

Fr - 2 = 3×2

Fr = 8N

Since Fr< μmg

Thus, Fr = 8N

Therefore, the frictional force between A and B is 8N.

  • The coefficient of friction is the measure of hindrance that the body experiences.
  • The frictional force is the force that causes hindrance to the motion of the object, and it is always in the direction opposite to that of motion of the body.

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