Question

3 blocks of mass 3kg 2kg and 1 kg placed side by side and a horizontal force of 24N applied on 3 kg block then what 2kg block experience force​

Answer 1

Answer:

8 N

Explanation:

a = F/m

a = 24/3

a = 8 m/s^2

F = ma

F = 2(8)

F = 16 N

24 N - 16 N

= 8 N

Answer 2

Given :-

Mass of first block = ${m}_{1}$= 3 kg

Mass of second block = ${m}_{2}$= 2 kg

Mass of third block = ${m}_{3}$= 1 kg

${F}_{x} = m{a}_{x}$

24N = (3+2+1)a

a = 4 ms-².

For 3 kg block,

24 - ${R}_{1} ={m}_{1}{a}_{x}$

24 -${R}_{1}$ = 12

${R}_{1}$= 12 N

Again For 2 kg block,

${R}_{1}-{R}_{2} ={m}_{2}{a}_{x}$

12 - ${R}_{2}$ = 4

${R}_{2}$= 8 N.