3 blocks of masses m1,m2,M3 are connected by massless unstrchable strings on a smooth surface .tention T2 is
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Answer:
Answer is 32 N
Explanation:
Since, the table is friction less ie, it is smooth therefore, force on the blocks is given by
F=(m1+m2+m3)a
⇒a=Fm1+m2+m3
=4010+6+4=4020
=2ms−2
Now the tension between 10 kg and 6 kg masses is given by
T2=(m1+m2)a
=(10+6)2=16×2
=32N
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