Question

3 bodies with masses 3kg, 6kg, and 2kg are pushed with 49.5N. Find acceleration and contact force.

Answer 1

Answer:

For all three parts, use Newton's second law, F = ma.

(a) The total mass of the system is

m = m1+m2+m3 = 12.5 kg + 24.7 kg + 31.0 kg = 68.2 kg

so the acceleration is

a = T1/m = (64.0 N) / (68.2 kg) = 0.938 m/s2.

(b) T1 = m1a = (12.5 kg)(0.938 m/s2) = 11.7 N

(c) T2 = (m1+m2)a = (12.5 kg + 24.7 kg)(0.938 m/s2)

= (37.2 kg)(0.938 m/s2) = 34.9 N

Step-by-step explanation:

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