3 bulbs are defective in a box of 10 bulbs. 2 bulbs are randomly selected from this box. These
bulbs are fixed in two bulb-holders installed in a room. Find the probability that the room will
be lighted after starting the electric supply.
Answers
Answered by
4
Answer:
Hoal
Step-by-step explanation:
Itz ......
defeactive 3
total 10
good ones 7
probability of lighting the room divide by total number of bulbs
7 / 10
Answered by
2
Answer:
It is 7/10
Step-by-step explanation:
Since three are defective,
Total bulbs that are non defective=10-3=7
P(room be lightened)=7/10
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