Question

3(bx + ay) = a- 6b; 3(ax-by) = -(6a +b)

Answer 1

open the bracket of both equations,on opening you will get:-

3bx + 3ay = a - 6b  ----(1)
3ax - 3by = -6a -b ----- (2)

Now multiply equation (1) by a and equation (2) by b,then you will get :-

3abx + 3 asquare y = a square - 6ba ----(1)
3abx - 3 bsquare y = -6ab -b square ----- (2)

Now equation (1) minus equation (2)

3abx + 3 a square y - (3abx - 3 b square y)=a square - 6ba - (-6ab -b square)

3abx + 3 a square y - 3abx + 3 b square y=a square - 6ba +6ab +b square

3 a square y + 3 b square y = a square + b square

3y(a square +b square) =a square + b square

3y = a square + b square divided by a square + b square

y = 1/3,substitute this value in equation 1 or 2,you will get x= - 2

Answer 2

Answer:

please give me my answer