Question

3 by 7 × 21 by 27÷3+8by 9​

Answer 1

Answer:

$\frac{3}{7} \times \frac{21}{27} \div 3 + \frac{8}{9} \\ = (\frac{3}{7} \times \frac{21}{27} \div 3 ) + \frac{8}{9} \\ = ( \frac{ \cancel 3}{ _{1 \: \: } \cancel 7} \times \frac{ \cancel{ 21}_{ \: \: \cancel 3_{ \: \: 1} }}{ \cancel{ 27} _{ \: \: 9} } \times \frac{1}{ \cancel 3} ) + \frac{8}{9} \\ = \frac{1}{9} + \frac{8}{9} \\ = \frac{1 + 8}{9} \\ = \frac{ \cancel 9}{ \cancel 9} \\ \boxed{ = \: \underline{ \underline{ 1}}}$