Math, asked by YashSingh05, 20 days ago

3 (c) 14.5 hours 25. Mini and Vinay are quiz masters preparing for a quiz. In x minutes, Mini makes y questions more than Vinay. If it were possible to reduce the time needed by each to make a question by two minutes, then in x minutes Mini would make 2y questions more than Vinay. How many questions does Mini make in x minutes? 2 (a) 1/4[2(x + y) - V(2x2 + 4y2)] (b) 1/4[2(x - y) - 1(2x + 4y2)] (c) Either a orb (d) 1/4 [2(x – y) - V(2x2 - 4y2)] D D - b​

Answers

Answered by jahnobidasgupta1
0

Answer:

Let Mini and Vinay take M and V minutes to frame a question respectively.

Mini takes M mins to frame 1 question.

Therefore Mini takes x mins to frame xM questions.

Vinay takes V mins to frame 1 question.

Therefore Vinay takes x mins to frame xV questions.

ATQ:

xM=xV+y(1)

Multiplying the above equation by 2 yields:

2xM=2xV+2y(1a)

Now, in the second scenario:

Mini takes (M-2) mins to frame 1 question.

Therefore Mini takes x mins to frame x(M−2) questions.

Vinay takes V-2 mins to frame 1 question.

Therefore Vinay takes x mins to frame x(V−2) questions.

Therefore ATQ:

xM−2=xV−2+2y(2)

Equating 2y from (1)a and 2 yields:

xM−2−xV−2=2xM−2xV

1M−2−1V−2=2M−2V

V−2−M+2(M−2)(V−2)=2V−2MMV

V−MMV−2M−2V+4=2V−2MMV

(V−M)MV=2(V−M)(MV−2M−2V+4)

MV=2MV−4M−4V+8

MV−4M−4V+8=0

Step-by-step explanation:

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