Question

3(c-2)=5(c+1)
using elimination method​

Answer 1

$Given \:simple \: equation : 3(c-2)=5(c+1)$

$\implies 3c - 6 = 5c + 5$

/* Subtract bothsides of the equation by 3c ,we get */

$\implies 3c - 3c - 6 = 5c -3c + 5$

$\implies - 6 = 2c + 5$

/* Subtract bothsides by 5 , we get */

$\implies - 6 -5 = 2c + 5 - 5$

$\implies - 11 = 2c$

/* Dividing each term by 2 , we get */

$\implies \frac{-11}{2} = \frac{2c}{2}$

$\implies \frac{-11}{2} = c$

Therefore.,

$\red{ Value \: of \: c } \green { = \frac{-11}{2}}$

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