Question

3
C.S.A of Sphere is numerically equal to C.S.A of Cylinder where
Ar=2h
B. h = 2
C. r=h
D. h=1/r​

Answer 1

Answer:

Cuboid whose length = l, breadth = b and height = h

(a) Volume of cuboid = lbh

(b) Total surface area of cuboid = 2 ( lb + bh + hl )

(c) Lateral surface area of cuboid = 2 h (l + b)

(d) Diagonal of cuboid = 222 lbh + +

• Cube whose edge = a

(a) Volume of cube = a3

(b) Lateral Surface area = 4a2

(c) Total surface area of cube = 6a2

(d) Diagonal of cube = a 3

• Cylinder whose radius = r, height = h

(a) Volume of cylinder = πr2

h

(b) Curved surface area of cylinder = 2πrh

(c) Total surface area of cylinder = 2πr (r + h)

• Cone having height = h, radius = r and slant height = l

(a) Volume of cone =

1 2

3

πr h

(b) Curved surface area of cone = πrl

SURFACE AREAS AND VOLUMES

CHAPTER 13