Question

3. Calculate the electrode potential of copper, if the concentration of CuSO4 is 0.206 M at
23.1 °C. Given that ECu2+/cu = + 0.34 V.​

Answer 1

Answer:

We know that, Ered=Ered∘+n0.0591log10[ion]

Putting the values of Ered∘=0.34 V,n=2 and [Cu2+]=0.1M

Ered=0.34+20.0591log10[0.1]

=0.34+0.02955×(−1)

=0.34−0.02955=0.31045

Explanation:

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