Question

3. Calculate the Kinetic energy of a bullet of mass 2.2 gm moving with a velocity 500 ms-1.​

Answer 1

Answer:

Explanation:

the mass is given in grams

first convert it into kg

so 2.2g=0.0022kg

v=500m/s

we know that K.E=(1/2)×mv²

K.E=(1/2)×0.0022×500²=(1/2)×22×25=275J

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