Question

3. Calculate the kinetic energy of an object weighing 600 kg moving at a velocity of 30 m/s​

Answer 1

Answer:

kinetic energy=1/2×mass of the body×(speed) ²

1/2×600kg×(30m/s) ²

300×900

2700J(ans)

please follow me...

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Kinetic\:energy=270\:KJ}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt:\implies Mass \: of \: object = 600 \: kg \\ \\ \tt:\implies Velocity = 30 \: m/s \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Kinetic \: energy \: of \: object = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Kinetic \: energy = \frac{1}{2} m {v}^{2} \\ \\ \tt: \implies Kinetic \: energy = \frac{1}{2} \times 600 \times {30}^{2} \\ \\ \tt: \implies Kinetic \: energy = \frac{1}{2} \times 600 \times 900 \\ \\ \tt: \implies Kinetic \: energy = 270000 \: J\\ \\ \green{\tt: \implies Kinetic \: energy = 270 \: KJ}\\\\ \blue{ \boxed{\bold{Some \: related \: formula}}} \\ \orange{\tt \circ \: Linear \: momentum = mv} \\ \\ \orange{\tt \circ \: Potential \: energy = mgh} \\ \\ \orange{\tt \circ \:Kinetic \: energy = 2 \: Linear \: momentum}$