Question

3) Calculate the mole fraction of solute in aqueous solution of glucose containing 18g of glucose (molecular mass - 180)in 500g water
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Answer 1

Answer:

Solving for molality

Molality = moles of solute / kilograms of solvent.

Molality = 18g / 180g per mole = 0.10 moles

Molality = 0.10 moles / 500g of water

Molality = 0.20 moles / 1 kg of water

Molality = 0.20 m

Solving for mole fraction

moles of glucose = 18g / 180 g/mole = 0.10 moles

moles of water = 500 g / 18 g per mole = 27.78 moles

mole fraction of solute = moles of solute / total moles in solution

mole fraction of solute = 0.10 mole / (0.10 mole + 27.78 moles)

mole fraction of solute = 0.10 mole / 27.88 moles

mole fraction of solute = 0.0036

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