Question

3. Calculate the number of moles of HCl present in 500 mL of .IM HCl solution.
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Answer 1

Answer:

Moles of solute = (0.50 L) (6.0 M) = 3.0 mol of HCl

Explanation:

Answer 2

Answer:

      n = 0.05 mol

Explanation:

Molarity = no of moles / volume of solution (in Litres)

0.1 M = n / 500 / 1000

0.1 M = n × 1000 / 500

0.1 M = n × 10 / 5

0.1 M = n × 2

n = 0.1 / 2

n = 1 / 20

n = 0.05 mol