Question

3. Calculate the work done in a resistor of
20 ohm carrying 5A of current in 3 hours.​

Answer 1

Answer:

I didn't understand this question

Answer 2

Answer:

1.5KWh

Explanation:

From P=W/t we will find workdone.

as P=I2R put it in above eq

soI2R=W/t

I2Rt=W

5^2*20*3=W

1500Wh=W

1.5KWh=W