3 capacitors each of capacitance 9pf are connected in series what is the total capacitance of the combination and what is the potential difference of each capacitor if the combination is connecter to 120 volt
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Capacitors C1, C2, C3 connected in series:
Equivalent capacitance of the combination, Ceq is related to C1, C2, C3 as follows:
1/Ceq = 1/C1 + 1/C2 + 1/C3
Given, C1 = C2 = C3 = 9 pF
So, 1/Ceq = 1/9 + 1/9 + 1/9 = 3/9 = 1/3
Thus, Ceq = 3pF.
The capacitors are connected to 120 V.
Potential difference across each capacitor is equal to 1/3 rd of 120 V.
So, the potential difference across each capacitor is 40 V.
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