3 cats on the vertices of equilateral triangle move along edges with equal and constant speed. Find probability that they will meet(any two or all three)
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Well, hello
Every cat has 2 choices, whether to go clockwise or anticlockwise.
So, total outcomes are 2^3 = 8
They don't meet only in 2 cases where all are moving clockwise or anticlockwise...
So probability of their meeting is 6/8 = 3/4
Every cat has 2 choices, whether to go clockwise or anticlockwise.
So, total outcomes are 2^3 = 8
They don't meet only in 2 cases where all are moving clockwise or anticlockwise...
So probability of their meeting is 6/8 = 3/4
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