Question

3 chairs and 2 tables cost rs 700 and 5 chairs and 3 tables cost rs 1100. What is the cost of 1 chairs and 2 tables

Answer 1

let the value of chair be X and table be Y

3x+2y=700------1eq.(×3)

5x+3y=1100----2eq.(×2)

9x+6x=2100

10x+6x=2200

(-) (-) (-)

_________________

-x =-100

x=100

put the value of x in equation 1

3×100+2y=700

2y=400

y=200

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Assumption :-

Cost of a chair be p.

Cost of a table be c.

★Condition is like that :-

3p + 2c = 700 ....... (1)

5p + 3c = 1100 ........ (2)

★Multiplying (1) × 3 and (2) × 2,

10p + 6c = 2200

9p + 6c = 2100

★Solving it we get :-

p = 100.

★Put value of in (1),

3p + 2c = 700

3(100) + 2c = 700

300 + 2c = 700

2c = 700 - 300

2c = 400

$\tt{\rightarrow c=\dfrac{400}{2}}$

c = 200.

★Hence,

★Cost of two chairs :-

= 2 × 100

= 200 rupees.

★Cost of two tables :-

= 2 × 200

= 400 rupees.