Question

3 charges are placed at the vertics of an equilateral ttiangle of side a as +q,+q,-q the foce experience by chage placed at a in direction (1) parallel to BC (2) normal to BC will equal to​

Answer 1

Answer:

Hey mate here is your answer.//

✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡✡

Explanation:

Force due to both charge at B and C are equal in magnitude and equal to

F 1= Q/²4πϵo a²,

Now from figure the angle between two F1 is θ=120  °,

Hence, net force F=√F21+F21+2F1F1 cos 120°,

⟹F=F1,

⟹F1 =  Q/²4πϵ0a².

 

​Hope it helps you.//✔✔✔

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