3 charges -q1,q2,-q3 shown in the figure find x component of force in -q1 is proportional to
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12th
Physics
Electric Charges and Fields
Gauss Law
The electric field componen...
PHYSICS
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Asked on December 26, 2019 by
Aakash Kathir
The electric field components due to a charge inside the cube of side 0.1 m are shown in figure.
where, E
x
=α, where α = 500 N/C-m, E
y
= 0, E
z
=0.
Calculate
(a) the flux through the cube and
(b) the charge inside the cube.
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ANSWER
Given length of the cube=0.1 m
E
y
=0, E
z
=0, E
x
=500
C−m
N
the flux through the cubeψ=∫E.ds=∫(E
x
i+E
y
j+E
z
k).ds=∫E
X
i.ds=E
x
x=αx=500x
ψ=(E
x
.A)
t=0.1
+(E
x
.A)
x=0.2
=E
x
Acos180+E
x
cos0=500×0.01×(−1)+500×0.2×0.01=−0.5+1=0.5
Cm
2
N
charge inside the cubeψ=∫E.ds=
E
0
q
⟹q=0.5×E
0
=0.5×8.85×10
−12
=4.425×10
−12
C
Explanation:
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