3. Check whether (5,-2), (6, 4) and (7,-2) are the vertices of an isosceles triangle
Answers
5 -2) (6 4) and (7 -2) are the vertices of an isosceles triangle
A ( 5 , -2)
B (6 , 4)
C ( 7 , -2)
Length of each sides
AB = √(6 - 5)² + (4+2)² = √( 1 + 36) = √37 units
BC = √(7 - 6)² + (-2-4)² = √(1 + 36) = √37 units
CA = √(7-5)² + (-2+2)² = √(4+0) = 2 units
AB = BC = √37
Hence verified that these vertices are of an isosceles triangles
Answer:
Step-by-step explanation:
We can check the same by application of 'distance formula' which is used to find the distance between two points whose coordinates are known.
If A(x₁, y₁) and B (x₂, y₂) represent 2 points in same plane, then by distance formula, the distance 'd' between these points is given by
d = √ (x₂ - x₁)² + (y₂ - y₁)²
Let the given points be written as:
A (5,-2)
B (6, 4)
C (7, -2)
AB = √(6 - 5)² + (4+2)² = √( 1 + 36) = √37 units
BC = √(7 - 6)² + (-2-4)² = √(1 + 36) = √37 units
CA = √(7-5)² + (-2+2)² = √(4+0) = 2 units
As, AB = BC = √37 units; The given vertices indeed form an isosceles trianlge.