Question

3. Check whether the following lengths can be the sides of a right triangle
(Pythagorean triplets)
a. 9 cm, 10 cm, 11 cm
b. 7cm, 24cm, 25 cm
c.1.7 cm, 1.5 cm, 0.8 cm
d. 0.9cm, 4 cm, 4.1 cm​

Answer 1

Step-by-step explanation:

$pythagorean \: triplets \: (9 \: 10 \: 11) \\ \\ a = 9\: b = 10 \: c = 11 \\ the \: pythagoras \: triples \: formula \: is \\ {c}^{2} = {a}^{2} + {b}^{2} \\ {11}^{2} = {9}^{2} + {10}^{2} \\ 121 = 81 + 100 \\ 121 = 181\\ left \: hand \: side \: is \: not \: equal \: to \: right \: hand \: side \: \\ therefore \: (9 \: 10 \: 11) \: not \: pythagorean \: triplet. \\ \\b) (7 \: 24 \: 25) \\ a = 7 \: \: b = 24 \: \: c = 25 \\ \\ {c}^{2} = {a}^{2} + {b}^{2} \\ {25}^{2} = {7}^{2} + {24}^{2} \\ 625 = 49 + 576 \\ 625 =625 \\ \\ therefore \: (7 \: \: 24 \: \: 25) \: are \: triplets$

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