Question

3.
Check which of the following are solutions of the equation x - 2y = 4 (√2 , 4√2)
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Answer 1

Answer:

It is not a solution of x-2y = 4

Step-by-step explanation:

$Given \ equation, x-2y=4 \\\\we \ have \ to \ check \ if \ (\sqrt{2} ,4\sqrt{2} ) \ is \ solution \ of \ the \ equation. \\ If \ it \ is \ solution,then \ LHS \ will \ be \ equal \ to \ RHS \ i.e., 4\\\\ Put \ x=\sqrt{2} \ and \ y=4\sqrt{2} \\\\ x-2y=\sqrt{2} -2(4\sqrt{2} ) = \sqrt{2}-8\sqrt{2} =-7\sqrt{2} \ is \ not \ equal \ to \ 4 \\\\ Hence, (\sqrt{2} ,4\sqrt{2} ) \ is \ not \ a \ solution \ of \ x-2y=4$