Question

3) COCKED ach Species z's -

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Answer 1

Answer:

Solution:

16w3 – u4w3.

= w3(16 – u4).

= w3(42 - ((u2)2).

= w3(4 + u2)(4 - u2).

= w3(4 + u2)(22 - u2).

= w3(4 + u2)(2 + u)(2 - u).

Answer: w3(4 + u2)(2 + u)(2 - u).