3 coins are tossed once. Find the probability of getting 2 tails
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3 coins are tossed simultaneously, then the outcomes will be ;
(HHH), (HHT) ,(HTT),(HTH) ,(THH), (HHT), (THT),(TTH)
Total no. of outcomes = 8
Outcomes with 2 tails = 4
Probability = 4/8 = 1/2
(HHH), (HHT) ,(HTT),(HTH) ,(THH), (HHT), (THT),(TTH)
Total no. of outcomes = 8
Outcomes with 2 tails = 4
Probability = 4/8 = 1/2
mysticd:
favorable out comes = 3, check shubham i.e 2tails
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S = {HHH HHT HTT TTT TTH THH THT HTH }
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m= 3
n = 8
probability = m/n
= 3/8
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m= 3
n = 8
probability = m/n
= 3/8
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